Optimal. Leaf size=115 \[ \frac{3 x^2 \text{PolyLog}\left (2,-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 x \text{PolyLog}\left (3,-\frac{b F^{c+d x}}{a}\right )}{b d^3 \log ^3(F)}+\frac{6 \text{PolyLog}\left (4,-\frac{b F^{c+d x}}{a}\right )}{b d^4 \log ^4(F)}+\frac{x^3 \log \left (\frac{b F^{c+d x}}{a}+1\right )}{b d \log (F)} \]
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Rubi [A] time = 0.131818, antiderivative size = 115, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {2190, 2531, 6609, 2282, 6589} \[ \frac{3 x^2 \text{PolyLog}\left (2,-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 x \text{PolyLog}\left (3,-\frac{b F^{c+d x}}{a}\right )}{b d^3 \log ^3(F)}+\frac{6 \text{PolyLog}\left (4,-\frac{b F^{c+d x}}{a}\right )}{b d^4 \log ^4(F)}+\frac{x^3 \log \left (\frac{b F^{c+d x}}{a}+1\right )}{b d \log (F)} \]
Antiderivative was successfully verified.
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Rule 2190
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{F^{c+d x} x^3}{a+b F^{c+d x}} \, dx &=\frac{x^3 \log \left (1+\frac{b F^{c+d x}}{a}\right )}{b d \log (F)}-\frac{3 \int x^2 \log \left (1+\frac{b F^{c+d x}}{a}\right ) \, dx}{b d \log (F)}\\ &=\frac{x^3 \log \left (1+\frac{b F^{c+d x}}{a}\right )}{b d \log (F)}+\frac{3 x^2 \text{Li}_2\left (-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 \int x \text{Li}_2\left (-\frac{b F^{c+d x}}{a}\right ) \, dx}{b d^2 \log ^2(F)}\\ &=\frac{x^3 \log \left (1+\frac{b F^{c+d x}}{a}\right )}{b d \log (F)}+\frac{3 x^2 \text{Li}_2\left (-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 x \text{Li}_3\left (-\frac{b F^{c+d x}}{a}\right )}{b d^3 \log ^3(F)}+\frac{6 \int \text{Li}_3\left (-\frac{b F^{c+d x}}{a}\right ) \, dx}{b d^3 \log ^3(F)}\\ &=\frac{x^3 \log \left (1+\frac{b F^{c+d x}}{a}\right )}{b d \log (F)}+\frac{3 x^2 \text{Li}_2\left (-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 x \text{Li}_3\left (-\frac{b F^{c+d x}}{a}\right )}{b d^3 \log ^3(F)}+\frac{6 \operatorname{Subst}\left (\int \frac{\text{Li}_3\left (-\frac{b x}{a}\right )}{x} \, dx,x,F^{c+d x}\right )}{b d^4 \log ^4(F)}\\ &=\frac{x^3 \log \left (1+\frac{b F^{c+d x}}{a}\right )}{b d \log (F)}+\frac{3 x^2 \text{Li}_2\left (-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 x \text{Li}_3\left (-\frac{b F^{c+d x}}{a}\right )}{b d^3 \log ^3(F)}+\frac{6 \text{Li}_4\left (-\frac{b F^{c+d x}}{a}\right )}{b d^4 \log ^4(F)}\\ \end{align*}
Mathematica [A] time = 0.0122258, size = 115, normalized size = 1. \[ \frac{3 x^2 \text{PolyLog}\left (2,-\frac{b F^{c+d x}}{a}\right )}{b d^2 \log ^2(F)}-\frac{6 x \text{PolyLog}\left (3,-\frac{b F^{c+d x}}{a}\right )}{b d^3 \log ^3(F)}+\frac{6 \text{PolyLog}\left (4,-\frac{b F^{c+d x}}{a}\right )}{b d^4 \log ^4(F)}+\frac{x^3 \log \left (\frac{b F^{c+d x}}{a}+1\right )}{b d \log (F)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.053, size = 225, normalized size = 2. \begin{align*} -{\frac{{c}^{3}x}{b{d}^{3}}}-{\frac{3\,{c}^{4}}{4\,b{d}^{4}}}+{\frac{{x}^{3}}{bd\ln \left ( F \right ) }\ln \left ( 1+{\frac{b{F}^{dx}{F}^{c}}{a}} \right ) }+{\frac{{c}^{3}}{b\ln \left ( F \right ){d}^{4}}\ln \left ( 1+{\frac{b{F}^{dx}{F}^{c}}{a}} \right ) }+3\,{\frac{{x}^{2}}{b \left ( \ln \left ( F \right ) \right ) ^{2}{d}^{2}}{\it polylog} \left ( 2,-{\frac{b{F}^{dx}{F}^{c}}{a}} \right ) }-6\,{\frac{x}{b \left ( \ln \left ( F \right ) \right ) ^{3}{d}^{3}}{\it polylog} \left ( 3,-{\frac{b{F}^{dx}{F}^{c}}{a}} \right ) }+6\,{\frac{1}{b \left ( \ln \left ( F \right ) \right ) ^{4}{d}^{4}}{\it polylog} \left ( 4,-{\frac{b{F}^{dx}{F}^{c}}{a}} \right ) }-{\frac{{c}^{3}\ln \left ( a+b{F}^{dx}{F}^{c} \right ) }{b\ln \left ( F \right ){d}^{4}}}+{\frac{{c}^{3}\ln \left ({F}^{dx}{F}^{c} \right ) }{b\ln \left ( F \right ){d}^{4}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.12446, size = 180, normalized size = 1.57 \begin{align*} \frac{x^{4}}{4 \, b} - \frac{\log \left (F^{d x}\right )^{4}}{4 \, b d^{4} \log \left (F\right )^{4}} + \frac{\log \left (\frac{F^{d x} F^{c} b}{a} + 1\right ) \log \left (F^{d x}\right )^{3} + 3 \,{\rm Li}_2\left (-\frac{F^{d x} F^{c} b}{a}\right ) \log \left (F^{d x}\right )^{2} - 6 \, \log \left (F^{d x}\right ){\rm Li}_{3}(-\frac{F^{d x} F^{c} b}{a}) + 6 \,{\rm Li}_{4}(-\frac{F^{d x} F^{c} b}{a})}{b d^{4} \log \left (F\right )^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 1.54776, size = 327, normalized size = 2.84 \begin{align*} \frac{3 \, d^{2} x^{2}{\rm Li}_2\left (-\frac{F^{d x + c} b + a}{a} + 1\right ) \log \left (F\right )^{2} - c^{3} \log \left (F^{d x + c} b + a\right ) \log \left (F\right )^{3} +{\left (d^{3} x^{3} + c^{3}\right )} \log \left (F\right )^{3} \log \left (\frac{F^{d x + c} b + a}{a}\right ) - 6 \, d x \log \left (F\right ){\rm polylog}\left (3, -\frac{F^{d x + c} b}{a}\right ) + 6 \,{\rm polylog}\left (4, -\frac{F^{d x + c} b}{a}\right )}{b d^{4} \log \left (F\right )^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{F^{c + d x} x^{3}}{F^{c} F^{d x} b + a}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{F^{d x + c} x^{3}}{F^{d x + c} b + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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